Espress. help 2

[peter09]

ti ringrazio bit5, scrivo l'altra:

{[2°°x3\5-(1+1\2)°°]:[(1-1\2°°)°°+(1-1\2)°°°]}:3\40-10\11

grazie

[BIT5]

[math] \{ [ 2^2 \cdot \frac35 - (1+ \frac12 )^2] : [(1- ( \frac12)^2)^2 + (1- \frac12)^3] \} : \frac{3}{40} - \frac{10}{11} = [/math]

[math] \{ [ 4 \cdot \frac35 - (\frac22+ \frac12)^2] : [(1- \frac14)^2 + (\frac22- \frac12)^3] \} : \frac{3}{40} - \frac{10}{11} = [/math]

[math] \{ [ \frac{12}{5} - \frac94] : [( \frac44 - \frac14)^2 + (\frac12)^3] \} : \frac{3}{40} - \frac{10}{11} = [/math]

[math] \{ [ \frac{12}{5} - \frac94] : [( \frac34)^2 + \frac18] \} : \frac{3}{40} - \frac{10}{11} = [/math]

[math] \{ [ \frac{12}{5} - \frac94] : [ \frac{9}{16} + \frac{2}{16}] \} : \frac{3}{40} - \frac{10}{11} = [/math]

[math] \{ [ \frac{48}{20} - \frac{45}{20}] : \frac{11}{16} \} : \frac{3}{40} - \frac{10}{11} = [/math]

[math] \{ [ \frac{3}{20} \cdot \frac{16}{11} \} : \frac{3}{40} - \frac{10}{11} = [/math]

[math] \frac{12}{55} \cdot \frac{40}{3} - \frac{10}{11} = [/math]

[math] \frac{32}{11} - \frac{10}{11} = \frac{22}{11} = 2[/math]