ALGEBRA ENTRO LE 13:00 :)

[ValeSLB]

1- [( 6 a^9 b^7 c^3) : (- 2ab^3 c) + 4/5 (a^4 b^2 c)^2 ] : ( -11 va^6 b^2 c^2)

2- {[( - 5/2 a) * (4b^2 c) + ( 25/3 ab^2 c])]^2 : ( 25/9 ab^3 c)}^3 - 4/5 a^3 b^3 c^3

3- [( 2/7 a^5 b^7 c^9) : ( 3/14 a^3 b^5 c^7) - 1/3 (abc)^2]^3 : [( a^2 b^2 c^7) : ( 1/7 ab^2 c^6)]

4- [( - 12/15 a^7 b^9 c^6) : ( 36/45 a^6 b^8 c^5)]^3 : [7abc * (2a^2) * ( - 1/14 b^2 c^2)]

Grazie mille:)

[19alexia97]

1-
(-3a^8 b^4 c^2 + 4/5 a^8 b^4 c^2):(-11 a^6 b^2 c^2)
(-11/5 a^8 b^4 c^2) : (-11 a^6 b^2 c^2)
1/5 a^2 b^2

Aggiunto 4 minuti più tardi:

4-
[( -4/5 a^7 b^9 c^6):(4/5 a^6 b^8 c^5)]^3 : (-1 a^3 b^3 c^3)
(-1 a^3 b^3 c^3):(-1 a^3 b^3 c^3)
1

Aggiunto 4 minuti più tardi:

3-
[(3 a^2 b^2 c^2-1/3 a^2 b^2 c^2)^2 : (1/7 ac)
(8/3 a^2 b^2 c^2)^2 : (1/7 ac)
64/63 a^3 b^4 c^3

[92kiaretta]

2)

[math]{[(-\frac{5}{2})*{4b^{2}c)+(\frac{25}{3}ab^{2}c)]^{2}: (\frac{25}{9}ab^{3}c)}^{3}-\frac{4}{5}a^{3}b^{3}c^{3} [/math]

[math]{[-10ab^{2}c+(\frac{25}{3}ab^{2}c)]^{2}:[\frac{25}{9}ab^{3}c]}^{3}-\frac{4}{5}a^{3}b^{3}c^{3} [/math]

[math]{[\frac{-30ab^{2}c+25ab^{2}c}{3}]^{2}:[\frac{25}{9}ab^{3}c]}^{3}-\frac{4}{5}a^{3}b^{3}c^{3} [/math]

[math]{[-\frac{5}{3}ab^{2}c]^{2}:[\frac{25}{9}ab^{3}c]}^{3}-\frac{4}{5}a^{3}b^{3}c^{3} [/math]

[math]{\frac{25}{9}a^{2}b^{4}c^{2}:[\frac{25}{9}ab^{3}c]}^{3}-\frac{4}{5}a^{3}b^{3}c^{3} [/math]

[math]{abc}^{3}-\frac{4}{5}a^{3}b^{3}c^{3} [/math]

[math] a^{3}b^{3}c^{3}-\frac{4}{5}a^{3}b^{3}c^{3} [/math]

[math]\frac{5 a^{3}b^{3}c^{3}-4 a^{3}b^{3}c^{3}}{5}=\frac{1}{5} a^{3}b^{3}c^{3}[/math]

[tiscali]

@Alexia: ma che diavolo hai scritto? :S

[math][(6a^9b^7c^3) : (-2ab^3c) + \frac{4}{5} (a^4b^2c)^2] : (-11a^6b^2c^2)[/math]

[math][(-3a^8b^4c^2) + \frac{4}{5}(a^8b^4c^4)] : (-11a^6b^2c^2)[/math]

[math][-3a^8b^4c^2 + \frac{4}{5}a^8b^4c^4] : (-11a^6b^2c^2)[/math]

[math][\frac{-15 + 4}{5}a^8b^4c^2] \cdot (-\frac{1}{11}a^6b^2c^2)[/math]

[math]-\frac{\not{11}^{1}}{5}a^8b^4c^2 \cdot -\frac{1}{\not{11}^{1}}a^6b^2c^2 = \frac{1}{5}a^2b^2[/math]

2)

[math]\left \{ [(-\frac{5}{2}a) \cdot (4b^2c) + (\frac{25}{3}ab^2c)]^2 : (\frac{25}{9}ab^3c) \right \}^3 - \frac{4}{5}a^3b^3c^3 = [/math]

[math]\left \{[-\frac{20}{2}ab^2c + \frac{25}{3}ab^2c)]^2 : (\frac{25}{9}ab^3c) \right \}^3 - \frac{4}{5}a^3b^3c^3[/math]

[math]\left \{[\frac{-60 + 50}{6}ab^2c]^2 : (\frac{25}{9}ab^3c) \right \}^3 - \frac{4}{5}a^3b^3c^3[/math]

[math]\left \{\frac{\not{100}^{4}}{\not{36}^{4}} ab^2c \cdot \frac{\not{9}^{1}}{\not{25}^{1}}ab^3c \right \}^3 - \frac{4}{5}a^3b^3c^3[/math]

[math]\left \{\frac{\not{4}^{1}}{\not{4}^{1}} \right \}^3 - \frac{4}{5}a^3b^3c^3 \to 1 - \frac{4}{5}a^3b^3c^3 = \frac{1}{5}a^3b^3^c^3[/math]

3)

[math][(\frac{2}{7}a^5b^7c^9) : (\frac{3}{14}a^3b^5b^7) - \frac{1}{3}(abc)^2]^3 : [(a^2b^2c^7) : (\frac{1}{7}ab^2c^6)] [/math]

[math][(\frac{2}{\not{7}^{1}}a^5b^7c^9) \cdot (\frac{\not{14}^{2}}{3}a^3b^5c^7) - \frac{1}{3}a^2b^2c^2]^3 : [7ac] = [/math]

[math][\frac{4}{3}a^2b^2c^2 - \frac{1}{3}a^2b^2c^2]^3 : [7ac][/math]

[math][\frac{4 - 1}{3}a^2b^2c^2]^3 \cdot [\frac{1}{7}ac][/math]

[math][\frac{\not{3}}{\not{3}}a^2b^2c^2]^3 \cdot \frac{1}{7}ac [/math]

[math]a^6b^6c^6 \cdot \frac{1}{7}ac \to \frac{1}{7}a^5b^6c^5[/math]

4)

[math][(-\frac{12}{15}a^7b^9c^6) : (\frac{36}{45}a^6b^8c^5)]^3 : [7abc \cdot (2a^2) \cdot (-\frac{1}{14}b^2c^2)][/math]

[math][(-\frac{\not{12}^{1}}{\not{15}^{1}}a^7b^9c^6) \cdot (\frac{\not{45}^{3}}{\not{36}^{3}}a^6b^8c^5)]^3 : [7abc \cdot (2a^2) \cdot (-\frac{1}{14}b^2c^2)[/math]

[math][-\frac{\not{3}}{\not{3}}a^3b^3c^3] \cdot [-\frac{\not{14}}{\not{14}}a^3b^3c^3] = 1[/math]