Espressioniii!!

[mmmica12]

V4^2+7+(2^4+2x5)+V1^3+3x(5^2-1-4^2)

V(9/4-13/15-17/18-1/20)x7/2

graziee

[Ali Q]

Ciao, Mmmica!
Ecco le soluzioni:

1) √[4^2+7+(2^4+2x5)]+ √[1^3+3x(5^2-1-4^2)]=
= √[4^2+7+(16+10)] + √[1^3+3x(25-1-16)]=
= √(16+7+26)+ √( 1+3x8 )=
= √(16+7+26)+ √(1+24)=
= √49+ √25=
=7+ 5 = 12

2)√ [(9/4-13/15-17/18-1/20)x7/2] =
= √ [(405-156-170-9)/180x7/2] =
=√ (70/180x7/2) =
=√ (7/18x7/2) =
=√ (49/36) = ± 7/6

Ciao, a presto!