Devo risolvere queste espressioni
radice quadrata[(6+4-1)x2+(5x6-3allaseconda+2)-(2allaterza+3x2)]:3 = 3
radice quadrata[(6allaterzax2allaterza:4allaterza):(10allaquarta:5allaquarta-7)x3allaquarta]:(3allaterzax3allaseconda)= 1
radice quadrata[(6allaterzax2allaterza:4allaterza):(10allaquarta:5allaquarta-7)x3allaquarta]:(3allaterzax3allaseconda)= 1
Risposte
Ecco a te:
√{[(6+4-1)x2+(5x6-3^2+2)-(2^3+3x2)]:3} =
=√{[9x2+(30-9+2)-(8+6)]:3} =
=√[(18+ 23- 14):3] =
=√(27:3) =
=√9 = 3
√{[(6^3x2^3:4^3): (10^4:5^4-7)x3^4]: (3^3x3^2)}=
=√{[(12^3:4^3): (2^4-7)x3^4]: 3^5}=
=√{[3^3: (16-7)x3^4]: 3^5}=
=√[(3^3: 9x3^4): 3^5]=
=√[(3^3: 3^2 x3^4): 3^5]=
=√[(3^1 x3^4): 3^5]=
=√(3^5: 3^5)=
=√1= 1
Ciao!
√{[(6+4-1)x2+(5x6-3^2+2)-(2^3+3x2)]:3} =
=√{[9x2+(30-9+2)-(8+6)]:3} =
=√[(18+ 23- 14):3] =
=√(27:3) =
=√9 = 3
√{[(6^3x2^3:4^3): (10^4:5^4-7)x3^4]: (3^3x3^2)}=
=√{[(12^3:4^3): (2^4-7)x3^4]: 3^5}=
=√{[3^3: (16-7)x3^4]: 3^5}=
=√[(3^3: 9x3^4): 3^5]=
=√[(3^3: 3^2 x3^4): 3^5]=
=√[(3^1 x3^4): 3^5]=
=√(3^5: 3^5)=
=√1= 1
Ciao!