Buona seraa!:) ........mi serve una mano i aritmetica.!

[alicee:3]

1) √36x(6-2)^2
___________
5^2x2^4

2) √144:3^2x7^4
___________
49x(11+1)^2

3) √169x121x5^2
____________
625x13^2x11^4

4) √(5+3)^4:8^2
___________
14^2x2^6

5) √3^6: (6-3)^4
_____________
5^4x3^8

6) √36x4x(14+2x11)
______________
(20+5)x18^2


vi pregoo :)

[Ali Q]

Soluzioni:

1) [√36x(6-2)^2]/(5^2x2^4)= (6x 4^2)/(25 x 2^4) = (6x 2^4)/(25 x 2^4) = 6/25

2) (√144:3^2x7^4)/ [49x(11+1)^2] = (12:9x7^4)/(7^2 x 12^2)= (1:9x7^2)/12 = (7^2)/(9x 12) = 49/108

3) (√169x121x5^2)/(625x13^2x11^4) = (13 x 11^2 x 5^2)/(5^4 x 13^2 x 11^4) = 1/(5^2 x 13 x 11^2) = 1/39325

4) [√(5+3)^4:8^2]/(14^2x2^6) = (√8^4:8^2)/(14^2x2^6) = (8^2:8^2)/(14^2x2^6) = 1/(14^2x2^6) = 1/12544

5) [√3^6: (6-3)^4]/ (5^4x3^8 ) = (3^3: 3^4)/(5^4x3^8 )= 3^(-1)/(5^4x3^8 )= 1/(5^4x3^9)

6) [√36x4x(14+2x11)]/[(20+5)x18^2] = [6x4x(14+22)]/(25x18^2)= (6x4x36)/(25x18^2)= (6x4x2x 18 )/(25x18^2)= (6x4x2)/(25x18 )= (6x4x2)/(25x3 x6)= (4x2)/(25 x 3) = 8/ 75.

Ciao!