Algebra..!

mmmica12
Mi aiutate perfavore!?grazie

-x^2y+3/2x-4/3x^2y-3/4x+3y+2/3x^2y-3y

-7/8abc-1/5a^3+1/2a^2-1/3a^3+1/4abc+5/8abc


a-(-a^3)+7/5x-11/4a-7/2a^3-3/10x-(-3/8a)

Risposte
Ali Q
Ecco a te:

-x^2y+3/2x-4/3x^2y-3/4x+3y+2/3x^2y-3y =
= -x^2y+3/2x-4/3x^2y-3/4x+3y+2/3x^2y-3y =
= x^2y (-1 -4/3 +2/3)+3/2x-3/4x+3y-3y =
= x^2 y (-3/3 -4/3 +2/3) +3/2 x- 3/4 x =
= -5/3 x^2y + (6/4 -3/4) x =
= -5/3 x^2y + 3/4 x =
= x(-5/3xy +3/4)



-7/8abc-1/5a^3+1/2a^2-1/3a^3+1/4abc+5/8abc =
= -7/8abc-1/5a^3+1/2a^2-1/3a^3+1/4abc+5/8abc =
= (-7/8 +1/4 +5/8 ) abc -1/5a^3+1/2a^2-1/3a^3 =
= (-7/8 +2/8 +5/8 ) abc -(1/5a^3+1/3a^3) +1/2a^2=
= 0 abc - (3/15 +5/15) a^3 +1/2 a^2 =
= -8/15 a^3 +1/2 a^2 =
= a^2 (-8/15 a +1/2)



a-(-a^3)+7/5x-11/4a-7/2a^3-3/10x-(-3/8a)=
= a + a^3+7/5x-11/4a-7/2a^3-3/10x +3/8a=
= a (1 -11/4 +3/8 ) + a^3( 1 -7/2)+ (7/5-3/10) x =
= a (8/8 -22/8 +3/8 ) + a^3 (2/2 -7/2) + (14/10 -3/10) x =
= 11/8 a -5/2 a^2 +11/10 x =
= 1/2 (11/4 -5a^3 +11/5 x)


Spero di non aver commesso errori.
Ciao!!!

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