Espressioni con le frazioni

[missbrunella1000]

sapete risolvere questa espressione?
{[1+3/2x(1/2-1/3)]^2x4/3+1/4}: (9/10+4/15)-3/2=
il risultato è 1/2 ma non so i passaggi
grazie

[lupuss]

ecco qui :)
{[1+3/2x(1/2-1/3)]^2x4/3+1/4}: (9/10+4/15)-3/2=
={[1+3/2x(3-2/6)]^2x4/3+1/4}: (27+8/30)-3/2=
={[1+3/2x1/6]^2x4/3+1/4}:35/30-3/2= (35/30 semplificato per 5 diventa 7/6)
={[1+1/4]^2x4/3+1/4}:7/6-3/2=
={[1+1/2+1/16]x4/3+1/4}:7/6-3/2=
={[16+8+1/16]x4/3+1/4}:7/6-3/2=
={25/16x4/3+1/4}:7/6-3/2= (16 e 4 si semplificano e diventano rispettivamente 4 e 1)
={25/12+1/4}:7/6-3/2=
={25+3/12}:7/6-3/2=
=28/12:7/6-3/2= (28/12 si semplifica per 4 e diventa 7/3)
=7/3x6/7-3/2= (7 e 7 si semplificano e anche 3 e 6)
=2-3/2=
=4-3/2=
=1/2.

[tiscali]

[math]\left \{ [ 1 + \frac{3}{2} \cdot (\frac{1}{2} - \frac{1}{3})]^2 \cdot \frac{4}{3} + \frac{1}{4} \right \} : (\frac{9}{10} + \frac{4}{15}) - \frac{3}{2} =[/math]

[math]\left \{ [ 1 + \frac{3}{2} \cdot (\frac{3 - 2}{6})]^2 \cdot \frac{4}{3} + \frac{1}{4} \right \} : (\frac{27 + 8}{30}) - \frac{3}{2} = [/math]

[math]\left \{ [ 1 + \frac{\not{3}^{1}}{2} \cdot \frac{1}{\not{6}^{2}}]^2 \cdot \frac{4}{3} + \frac{1}{4} \right \} : \frac{35}{30} - \frac{3}{2} = [/math]

[math]\left \{ [ \frac{ 4 + 1}{4}]^2 \cdot \frac{4}{3} + \frac{1}{4} \right \} : \frac{35}{30} - \frac{3}{2} = [/math]

[math]\left \{ \frac{25}{\not{16}^{4}} \cdot \frac{\not{4}^{1}}{3} + \frac{1}{4} \right \} : \frac{35}{30} - \frac{3}{2} = [/math]

[math]\left \{ \frac{25}{12} + \frac{1}{4} \right \} : \frac{35}{30} - \frac{3}{2} = [/math]

[math]\frac{25 + 3}{12} : \frac{35}{30} - \frac{3}{2} = [/math]

[math]\frac{\not{28}^{4}}{\not{12}^{2}} \cdot \frac{\not{30}^{5}}{\not{35}^{5}} - \frac{3}{2} = [/math]

[math]\frac{20}{10} - \frac{3}{2} = \to \frac{20 - 15}{10} = \frac{\not{5}^{1}}{\not{10}^{2}} = \frac{1}{2}[/math]

[missbrunella1000]

GRAZIE TANTE